So far we've studied pure rotation (an object spins in place) or pure translation (an object moves in a straight line). But in reality, wheels and spheres spin and move simultaneously. This combination is called rolling motion.
Definition: Rolling Without Slipping
Rolling without slipping occurs when:
- An object rotates about its own axis
- Its center of mass translates
- There is no slipping at the contact point between the object and the surface
The No-Slip Condition
Consider a disk of radius \( R \) rolling without slipping. If:
- Center-of-mass velocity: \( v_{cm} \)
- Angular velocity: \( \omega \)
Then:
\[ v_{cm} = \omega R \]
Proof: At the contact point, velocity must be zero:
\[ v_{\text{contact}} = v_{cm} - \omega R = 0 \implies v_{cm} = \omega R \]
Example: A ball of radius 0.1 m rolls without slipping on the ground. Its center moves at 2 m/s. What is its angular velocity?
\[ \omega = \frac{v_{cm}}{R} = \frac{2}{0.1} = 20 \text{ rad/s} \]
Velocity Components
At any instant, every point on a rolling object has two velocity components:
- Translational velocity: velocity of the center of mass (\( v_{cm} \))
- Rotational velocity: velocity relative to the center (\( \omega r' \), where \( r' \) is distance from axis)
Velocity Map
Different points on a disk:
- Contact point: \( v = 0 \) (no-slip condition)
- Center: \( v = v_{cm} \)
- Top point: \( v = 2v_{cm} \) (translational and rotational velocities add)
Energy of Rolling Motion
In rolling, total kinetic energy has two parts:
\[ K_{\text{total}} = K_{\text{translational}} + K_{\text{rotational}} \]
\[ K_{\text{total}} = \frac{1}{2}m v_{cm}^2 + \frac{1}{2}I\omega^2 \]
Using the No-Slip Condition
From \( v_{cm} = \omega R \):
\[ \omega = \frac{v_{cm}}{R} \]
\[ K_{\text{total}} = \frac{1}{2}m v_{cm}^2 + \frac{1}{2}I\left(\frac{v_{cm}}{R}\right)^2 \]
\[ K_{\text{total}} = \frac{1}{2}m v_{cm}^2 + \frac{I}{2R^2} v_{cm}^2 \]
\[ K_{\text{total}} = \frac{1}{2}\left(m + \frac{I}{R^2}\right) v_{cm}^2 \]
Shape Factor
We can write this more compactly:
\[ K_{\text{total}} = \frac{1}{2}m v_{cm}^2 \left(1 + \frac{I}{mR^2}\right) \]
Note: The value \( \frac{I}{mR^2} \) depends on object shape:
- Solid cylinder: \( \frac{I}{mR^2} = \frac{1}{2} \)
- Solid sphere: \( \frac{I}{mR^2} = \frac{2}{5} \)
- Hoop: \( \frac{I}{mR^2} = 1 \)
Numerical Example: Three Rolling Objects
Three objects (solid cylinder, sphere, hoop) with mass m = 2 kg and radius R = 0.1 m roll without slipping. Each has center-of-mass velocity v_cm = 3 m/s.
Solid cylinder: \[ I = \frac{1}{2}mR^2 = \frac{1}{2} \times 2 \times (0.1)^2 = 0.01 \text{ kg·m}^2 \]
\[ K = \frac{1}{2} \times 2 \times 3^2 + \frac{1}{2} \times 0.01 \times \left(\frac{3}{0.1}\right)^2 = 9 + 4.5 = 13.5 \text{ J} \]
Sphere: \[ I = \frac{2}{5}mR^2 = \frac{2}{5} \times 2 \times (0.1)^2 = 0.008 \text{ kg·m}^2 \]
\[ K = \frac{1}{2} \times 2 \times 3^2 + \frac{1}{2} \times 0.008 \times 30^2 = 9 + 3.6 = 12.6 \text{ J} \]
Hoop: \[ I = mR^2 = 2 \times (0.1)^2 = 0.02 \text{ kg·m}^2 \]
\[ K = \frac{1}{2} \times 2 \times 3^2 + \frac{1}{2} \times 0.02 \times 30^2 = 9 + 9 = 18 \text{ J} \]
Result: Sphere has minimum energy (most efficient); hoop has maximum.
Rolling Down an Inclined Plane
When an object is released on an incline, two things happen:
- Translation: object moves down
- Rotation: object spins
Deriving the Acceleration
Using energy conservation or force equations:
\[ a_{cm} = \frac{g \sin\theta}{1 + \frac{I}{mR^2}} \]
Comparison: If the object slides without rolling (\( I = 0 \)): \[ a_{\text{sliding}} = g\sin\theta \]
Note: A rolling object accelerates slower because energy is shared between translation and rotation.
What You Should Know
- No-slip condition: \( v_{cm} = \omega R \)
- Total kinetic energy: \( K = \frac{1}{2}m v_{cm}^2 + \frac{1}{2}I\omega^2 \)
- Shape effect: different objects have different energy distributions
- Inclined plane: acceleration is less than pure sliding
Preview of §11.2
Now that we understand rolling motion, what causes it? The answer: torque. Let's examine the forces at work and see how they produce rotation.
📚 See also: Halliday Vol 1, Ch 11, §11.1 — Rolling without slipping. 🔗 Reference: §10.4 (Rotational kinetic energy) — which we used for total energy here.
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