The Electric Field of a Charged Particle: Weaker with Distance ⚡
Today’s question 💭: Imagine a single point charge. How does it fill the space around it? Is the field stronger near it or farther away? And which direction does the field point? Let’s derive the answer directly from Coulomb’s law 👇
Building the Formula Ourselves 🛠️
We want to find the electric field produced by a point charge $q$ at a distance $r$ from it. It’s simple: we place a test charge $q_0$ there. According to Coulomb’s law, the force acting on it is:
$$ F = kfrac{|q||q_۰|}{r^۲} $$
Now, we use the definition of the electric field ($E = F/q_0$). We just need to divide both sides by $q_0$; that $q_0$ cancels out, leaving us with:
$$ E = kfrac{|q|}{r^۲} tag{۱-۴} $$
This formula tells us two things: the field is directly proportional to the magnitude of the charge and inversely proportional to the square of the distance. In other words, if you double the distance, the field becomes one-fourth as strong. ✨
Direction of the Field: Which Way? 🧭
Remember that the direction of the field is the direction of the force exerted on a positive test charge. So:
Field of a positive charge → from the charge outward (radially, pointing out) ➡️
Field of a negative charge → from outside toward the charge (radially, pointing in) ⬅️