Problem 1 IYPT 2027

1. Invent yourself: Pinhole sunglasses

Optics

Problem Description & Analysis

Official Problem Statement

Investigate the optimal arrangement of pinholes in an opaque film to produce sunglasses that reduce light intensity and help correct short-sightedness.

Key Physics Concepts

Geometric Optics — Depth of Field

Each pinhole acts as a tiny aperture stop. As the hole diameter decreases, the cone of light passing through narrows, reducing the circle of confusion on the retina — allowing even myopic or hyperopic eyes to see a relatively sharper image.

dblur = D × |1/f − 1/v − 1/u|

where:
dblur : diameter of the blur (circle of confusion) on the retina — in metres (m)
D : pinhole diameter — in metres (m)
f : focal length of the eye’s lens — in metres (m)  ≈  0.017 m
v : image distance (lens to retina) — in metres (m)  ≈  0.017 m
u : object distance (object to lens) — in metres (m)

As D decreases, the blur circle shrinks and depth of field increases.

Wave Optics — Diffraction

Reducing the aperture too much introduces a wave-optics limit: when D approaches the wavelength of light, diffraction dominates and the Airy pattern blurs the image. Rayleigh’s resolution limit:

θmin = 1.22 × λ / D

where:
θmin : minimum resolvable angle (Rayleigh criterion) — in radians (rad)
λ : wavelength of light — in metres (m); green light: λ ≈ 550 nm = 550×10⁻⁹ m
D : pinhole diameter — in metres (m)
1.22 : Rayleigh constant (dimensionless, from Bessel function zero)

Conclusion: there is an optimal diameter that balances geometric blur (large D) and diffraction blur (small D).

Optimal Pinhole Diameter

At the point where geometric blur equals diffraction blur, the total blur is minimised. For image distance v (approximately the focal length of the eye, ≈ 17 mm) and green light (λ ≈ 550 nm):

Dopt ≈ √(2.44 × λ × v) ≈ 0.15 mm

where:
Dopt : optimal pinhole diameter — in metres (m)
λ : wavelength of light — in metres (m); green light: λ ≈ 550 nm = 550×10⁻⁹ m
v : retinal distance from lens — in metres (m); v ≈ 17 mm = 0.017 m
2.44 : Rayleigh diffraction constant (= 2 × 1.22) — dimensionless

This value matches commercially available pinhole glasses (0.1–0.3 mm holes).

Parameters to Investigate

  • Hole diameter D — directly controls depth of field and diffraction intensity
  • Hole spacing (pitch) — if too close, diffraction patterns from adjacent holes interfere
  • Arrangement pattern — square lattice vs. hexagonal lattice
  • Film thickness — thicker film = smaller acceptance angle = narrower field of view
  • Hole density — more holes = brighter image but higher interference risk

Suggested Experimental Procedure

  1. Fabricate several samples with different diameters (0.1–0.5 mm)
  2. Measure visual acuity for each sample using a Snellen chart
  3. Measure transmitted light intensity with a lux meter
  4. Determine the useful field of view by gradually rotating the glasses
  5. Compare results with the theoretical model above

Related Images

Interactive Simulation (Python)

This simulation runs directly in your browser — no Python installation needed. Initial loading may take a few seconds.

Press the button below to start.
(a) Blur circle diameter on the retina vs. hole diameter — shows that total blur reaches a minimum at optimal Dopt; diffraction dominates for smaller diameters, geometric blur for larger ones.
(b) Light transmission (%) vs. hole diameter — shows the quadratic dependence of transmitted intensity on the D/pitch ratio.
(c) Comparison of diffraction, geometric, and total blur values (in µm) — displayed for the user-selected diameter.

Python Code Lab

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